(x^2-0.25x)=0

Solution for (x^2-0.25x)=0 equation:

(x^2-0.25x)=0

We get rid of parentheses

x^2-0.25x=0

a = 1; b = -0.25; c = 0;
Δ = b2-4ac
Δ = -0.252-4·1·0
Δ = 0.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.25)-\sqrt{0.0625}}{2*1}=\frac{0.25-\sqrt{0.0625}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.25)+\sqrt{0.0625}}{2*1}=\frac{0.25+\sqrt{0.0625}}{2}
$